A body of mass 1 kg is thrown upwards with a velocity 20 ms -1 . It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 ms -2 )
Text Solution
Verified by ExpertsThe correct answer is:
A
The energy lost due to air friction is equal to difference of initial kinetic energy and final potential energy.
Initially body posses only kinetic energy and after attaining a height the kinetic energy is zero
Therefore, loss of energy = kE – PE
= kE – PE
= 
mv 2 – mgh= 
× 1 × 400 –1 × 18 × 10
= 200 –180 = 20 J
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